JOINS
CROSS JOIN
A CROSS JOIN performs a join between two tables that does not use an explicit join clause and results in the Cartesian product of two tables. A Cartesian product means each row of one table is combined with each row of the second table in the join. For example, if TABLEA has 20 rows and TABLEB has 20 rows, the result would be 20*20 = 400 output rows.
Example:
SELECT *
FROM TABLEA CROSS JOIN TABLEB;This can also be written as:
SELECT *
FROM TABLEA, TABLEB;Here’s an example of cross join in SQL between two tables:
Sample Table: TABLEA
+-------+---------+
| VALUE | NAME |
+-------+---------+
| 1 | ONE |
| 2 | TWO |
+-------+---------+Sample Table: TABLEB
+-------+--------+
| VALUE | NAME |
+-------+--------+
| 3 | THREE |
| 4 | FOUR |
+-------+--------+Now, If you execute the query:
SELECT *
FROM TABLEA CROSS JOIN TABLEB;Output:
+-------+--------+-------+--------+
| VALUE | NAME | VALUE | NAME |
+-------+--------+-------+--------+
| 1 | ONE | 3 | THREE |
| 1 | ONE | 4 | FOUR |
| 2 | TWO | 3 | THREE |
| 2 | TWO | 4 | FOUR |
+-------+--------+-------+--------+This is how cross joining happens between two tables:
More about Cross Join: Oracle documentation
INNER JOIN
An INNER JOIN is a JOIN operation that allows you to specify an explicit join clause.
Syntax
TableExpression [ INNER ] JOIN TableExpression { ON booleanExpression | USING clause }
You can specify the join clause by specifying ON with a boolean expression.
The scope of expressions in the ON clause includes the current tables and any tables in outer query blocks to the current SELECT. In the following example, the ON clause refers to the current tables:
-- Join the EMP_ACT and EMPLOYEE tables
-- select all the columns from the EMP_ACT table and
-- add the employee's surname (LASTNAME) from the EMPLOYEE table
-- to each row of the result
SELECT SAMP.EMP_ACT.*, LASTNAME
FROM SAMP.EMP_ACT JOIN SAMP.EMPLOYEE
ON EMP_ACT.EMPNO = EMPLOYEE.EMPNO
-- Join the EMPLOYEE and DEPARTMENT tables,
-- select the employee number (EMPNO),
-- employee surname (LASTNAME),
-- department number (WORKDEPT in the EMPLOYEE table and DEPTNO in the
-- DEPARTMENT table)
-- and department name (DEPTNAME)
-- of all employees who were born (BIRTHDATE) earlier than 1930.
SELECT EMPNO, LASTNAME, WORKDEPT, DEPTNAME
FROM SAMP.EMPLOYEE JOIN SAMP.DEPARTMENT
ON WORKDEPT = DEPTNO
AND YEAR(BIRTHDATE) < 1930
-- Another example of "generating" new data values,
-- using a query which selects from a VALUES clause (which is an
-- alternate form of a fullselect).
-- This query shows how a table can be derived called "X"
-- having 2 columns "R1" and "R2" and 1 row of data
SELECT *
FROM (VALUES (3, 4), (1, 5), (2, 6))
AS VALUESTABLE1(C1, C2)
JOIN (VALUES (3, 2), (1, 2),
(0, 3)) AS VALUESTABLE2(c1, c2)
ON VALUESTABLE1.c1 = VALUESTABLE2.c1
-- This results in:
-- C1 |C2 |C1 |2
-- -----------------------------------------------
-- 3 |4 |3 |2
-- 1 |5 |1 |2
-- List every department with the employee number and
-- last name of the manager
SELECT DEPTNO, DEPTNAME, EMPNO, LASTNAME
FROM DEPARTMENT INNER JOIN EMPLOYEE
ON MGRNO = EMPNO
-- List every employee number and last name
-- with the employee number and last name of their manager
SELECT E.EMPNO, E.LASTNAME, M.EMPNO, M.LASTNAME
FROM EMPLOYEE E INNER JOIN
DEPARTMENT INNER JOIN EMPLOYEE M
ON MGRNO = M.EMPNO
ON E.WORKDEPT = DEPTNOLEFT OUTER JOIN
A LEFT OUTER JOIN performs a join between two tables that requires an explicit join clause but does not exclude unmatched rows from the first table.
Example:
SELECT
ENAME,
DNAME,
EMP.DEPTNO,
DEPT.DEPTNO
FROM
SCOTT.EMP LEFT OUTER JOIN SCOTT.DEPT
ON EMP.DEPTNO = DEPT.DEPTNO; Even though ANSI syntax is the recommended way, it is likely to encounter legacy syntax very often. Using (+) within a condition determines which side of the equation to be considered as outer.
SELECT
ENAME,
DNAME,
EMP.DEPTNO,
DEPT.DEPTNO
FROM
SCOTT.EMP,
SCOTT.DEPT
WHERE
EMP.DEPTNO = DEPT.DEPTNO(+);Here’s an example of Left Outer Join between two tables:
Sample Table: EMPLOYEE
+-----------+---------+
| NAME | DEPTNO |
+-----------+---------+
| A | 2 |
| B | 1 |
| C | 3 |
| D | 2 |
| E | 1 |
| F | 1 |
| G | 4 |
| H | 4 |
+-----------+---------+Sample Table: DEPT
+---------+--------------+
| DEPTNO | DEPTNAME |
+---------+--------------+
| 1 | ACCOUNTING |
| 2 | FINANCE |
| 5 | MARKETING |
| 6 | HR |
+---------+--------------+Now, If you execute the query:
SELECT
*
FROM
EMPLOYEE LEFT OUTER JOIN DEPT
ON EMPLOYEE.DEPTNO = DEPT.DEPTNO;Output:
+-----------+---------+---------+--------------+
| NAME | DEPTNO | DEPTNO | DEPTNAME |
+-----------+---------+---------+--------------+
| F | 1 | 1 | ACCOUNTING |
| E | 1 | 1 | ACCOUNTING |
| B | 1 | 1 | ACCOUNTING |
| D | 2 | 2 | FINANCE |
| A | 2 | 2 | FINANCE |
| C | 3 | | |
| H | 4 | | |
| G | 4 | | |
+-----------+---------+---------+--------------+RIGHT OUTER JOIN
A RIGHT OUTER JOIN performs a join between two tables that requires an explicit join clause but does not exclude unmatched rows from the second table.
Example:
SELECT
ENAME,
DNAME,
EMP.DEPTNO,
DEPT.DEPTNO
FROM
SCOTT.EMP RIGHT OUTER JOIN SCOTT.DEPT
ON EMP.DEPTNO = DEPT.DEPTNO; As the unmatched rows of SCOTT.DEPT are included, but unmatched rows of SCOTT.EMP are not, the above is equivalent to the following statement using LEFT OUTER JOIN.
SELECT
ENAME,
DNAME,
EMP.DEPTNO,
DEPT.DEPTNO
FROM
SCOTT.DEPT RIGHT OUTER JOIN SCOTT.EMP
ON DEPT.DEPTNO = EMP.DEPTNO;Here’s an example of Right Outer Join between two tables:
Sample Table: EMPLOYEE
+-----------+---------+
| NAME | DEPTNO |
+-----------+---------+
| A | 2 |
| B | 1 |
| C | 3 |
| D | 2 |
| E | 1 |
| F | 1 |
| G | 4 |
| H | 4 |
+-----------+---------+Sample Table: DEPT
+---------+--------------+
| DEPTNO | DEPTNAME |
+---------+--------------+
| 1 | ACCOUNTING |
| 2 | FINANCE |
| 5 | MARKETING |
| 6 | HR |
+---------+--------------+Now, If you execute the query:
SELECT
*
FROM
EMPLOYEE RIGHT OUTER JOIN DEPT
ON EMPLOYEE.DEPTNO = DEPT.DEPTNO;Output:
+-----------+---------+---------+--------------+
| NAME | DEPTNO | DEPTNO | DEPTNAME |
+-----------+---------+---------+--------------+
| A | 2 | 2 | FINANCE |
| B | 1 | 1 | ACCOUNTING |
| D | 2 | 2 | FINANCE |
| E | 1 | 1 | ACCOUNTING |
| F | 1 | 1 | ACCOUNTING |
| | | 5 | MARKETING |
| | | 6 | HR |
+-----------+---------+---------+--------------+Oracle (+) syntax equivalent for the query is:
SELECT *
FROM EMPLOYEE, DEPT
WHERE EMPLOYEE.DEPTNO(+) = DEPT.DEPTNO;FULL OUTER JOIN
A FULL OUTER JOIN performs a join between two tables that requires an explicit join clause but does not exclude unmatched rows in either table. In other words, it returns all the rows in each table.
Example:
SELECT
*
FROM
EMPLOYEE FULL OUTER JOIN DEPT
ON EMPLOYEE.DEPTNO = DEPT.DEPTNO; Here’s an example of Full Outer Join between two tables:
Sample Table: EMPLOYEE
+-----------+---------+
| NAME | DEPTNO |
+-----------+---------+
| A | 2 |
| B | 1 |
| C | 3 |
| D | 2 |
| E | 1 |
| F | 1 |
| G | 4 |
| H | 4 |
+-----------+---------+Sample Table: DEPT
+---------+--------------+
| DEPTNO | DEPTNAME |
+---------+--------------+
| 1 | ACCOUNTING |
| 2 | FINANCE |
| 5 | MARKETING |
| 6 | HR |
+---------+--------------+Now, If you execute the query:
SELECT
*
FROM
EMPLOYEE FULL OUTER JOIN DEPT
ON EMPLOYEE.DEPTNO = DEPT.DEPTNO;Output
+-----------+---------+---------+--------------+
| NAME | DEPTNO | DEPTNO | DEPTNAME |
+-----------+---------+---------+--------------+
| A | 2 | 2 | FINANCE |
| B | 1 | 1 | ACCOUNTING |
| C | 3 | | |
| D | 2 | 2 | FINANCE |
| E | 1 | 1 | ACCOUNTING |
| F | 1 | 1 | ACCOUNTING |
| G | 4 | | |
| H | 4 | | |
| | | 6 | HR |
| | | 5 | MARKETING |
+-----------+---------+---------+--------------+Here the columns that do not match has been kept NULL.
ANTIJOIN
An antijoin returns rows from the left side of the predicate for which there are no corresponding rows on the right side of the predicate. It returns rows that fail to match (NOT IN) the subquery on the right side.
SELECT * FROM employees
WHERE department_id NOT IN
(SELECT department_id FROM departments
WHERE location_id = 1700)
ORDER BY last_name;Here’s an example of Anti Join between two tables:
Sample Table: EMPLOYEE
+-----------+---------+
| NAME | DEPTNO |
+-----------+---------+
| A | 2 |
| B | 1 |
| C | 3 |
| D | 2 |
| E | 1 |
| F | 1 |
| G | 4 |
| H | 4 |
+-----------+---------+Sample Table: DEPT
+---------+--------------+
| DEPTNO | DEPTNAME |
+---------+--------------+
| 1 | ACCOUNTING |
| 2 | FINANCE |
| 5 | MARKETING |
| 6 | HR |
+---------+--------------+Now, If you execute the query:
SELECT
*
FROM
EMPLOYEE WHERE DEPTNO NOT IN
(SELECT DEPTNO FROM DEPT);Output:
+-----------+---------+
| NAME | DEPTNO |
+-----------+---------+
| C | 3 |
| H | 4 |
| G | 4 |
+-----------+---------+The output shows that only the rows of EMPLOYEE table, of which DEPTNO were not present in DEPT table.
SEMIJOIN
A semijoin query can be used, for example, to find all departments with at least one employee whose salary exceeds 2500.
SELECT * FROM departments
WHERE EXISTS
(SELECT 1 FROM employees
WHERE departments.department_id = employees.department_id
AND employees.salary > 2500)
ORDER BY department_name; This is more efficient than the full join alternatives, as inner joining on employees then giving a where clause detailing that the salary has to be greater than 2500 could return the same department numerous times. Say if the Fire department has n employees all with salary 3000, select * from departments, employees with the necessary join on ids and our where clause would return the Fire department n times.
JOIN
The JOIN operation performs a join between two tables, excluding any unmatched rows from the first table. From Oracle 9i forward, the JOIN is equivalent in function to the INNER JOIN. This operation requires an explicit join clause, as opposed to the CROSS JOIN and NATURAL JOIN operators.
Example:
select t1.*,
t2.DeptId
from table_1 t1
join table_2 t2 on t2.DeptNo = t1.DeptNoOracle documentation:
NATURAL JOIN
NATURAL JOIN requires no explitic join condition; it builds one based on all the fields with the same name in the joined tables.
create table tab1(id number, descr varchar2(100));
create table tab2(id number, descr varchar2(100));
insert into tab1 values(1, 'one');
insert into tab1 values(2, 'two');
insert into tab1 values(3, 'three');
insert into tab2 values(1, 'ONE');
insert into tab2 values(3, 'three');The join will be done on the fields ID and DESCR, common to both the tables:
SQL> select *
2 from tab1
3 natural join
4 tab2;
ID DESCR
---------- ----------
3 threeColumns with different names will not be used in the JOIN condition:
SQL> select *
2 from (select id as id, descr as descr1 from tab1)
3 natural join
4 (select id as id, descr as descr2 from tab2);
ID DESCR1 DESCR2
---------- ---------- ----------
1 one ONE
3 three threeIf the joined tables have no common columns, a JOIN with no conditions will be done:
SQL> select *
2 from (select id as id1, descr as descr1 from tab1)
3 natural join
4 (select id as id2, descr as descr2 from tab2);
ID1 DESCR1 ID2 DESCR2
---------- ---------- ---------- ----------
1 one 1 ONE
2 two 1 ONE
3 three 1 ONE
1 one 3 three
2 two 3 three
3 three 3 three