racket

Recursion

Using define

#lang racket
(define (sum-of-list l)
  (if (null? l)
      0
      (+ (car l)
         (sum-of-list (cdr l)))))
(sum-of-list '(1 2 3 4 5)) ;; => 15

Using let-rec

#lang racket
(letrec ([sum-of-list (λ (l)
                        (if (null? l)
                            0
                            (+ (car l) (sum-of-list (cdr l)))))])
  (sum-of-list '(1 2 3 4 5)))
;; => 15

It is possible to write mutually recursive functions with letrec:

#lang racket
(letrec ([even? (λ (n) (if (= n 0) #t (odd?  (sub1 n))))]
         [odd?  (λ (n) (if (= n 0) #f (even? (sub1 n))))])
  (list (even? 3)
        (odd? 5)))
;; => '(#f #t)

Using a named let

A normal let form binds each value to its corresponding identifier, before executing the body. With a “named let”, the body can then recursively be re-executed, passing a new value for each identifier.

#lang racket
(let sum-of-list ([l '(1 2 3)])
  (if (null? l)
      0
      (+ (car l) (sum-of-list (cdr l)))))
;; => 15

It is common to use rec as the name for the let, which gives:

#lang racket
(let rec ([l '(1 2 3 4 5)])
  (if (null? l)
      0
      (+ (car l) (rec (cdr l)))))
;; => 15

Using rec

#lang racket
(require mzlib/etc)
((rec sum-of-list
   (λ (l)
     (if (null? l)
         0
         (+ (car l) (sum-of-list (cdr l))))))
 '(1 2 3 4 5))
;; => 15

;; Outside of the rec form, sum-of-list gives an error:
;; sum-of-list: undefined;
;;  cannot reference an identifier before its definition

This is similar to define, but the sum-of-list identifier is not visible outside of the rec form.

To avoid using an explicit λ, it is possible to replace sum-of-list with (sum-of-list args ...):

#lang racket
(require mzlib/etc)
((rec (sum-of-list l)
   (if (null? l)
       0
       (+ (car l) (sum-of-list (cdr l)))))
 '(1 2 3 4 5))
;; => 15

Using higher-order functions instead of recursion

It is common practice to use higher order functions instead of recursion, if there is a higher order function which expresses the right recursion pattern. In our case, sum-of-numbers can be defined using foldl:

#lang racket
(define (sum-of-numbers l)
  (foldl + 0 l))
(sum-of-numbers '(1 2 3 4 5)) ;; => 15

It is possible to call foldl directly on the list:

#lang racket
(foldl + 0 '(1 2 3 4 5)) ;; => 15

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